Sql Injection Challenge 5 Security Shepherd 'link' -

Input: 5' AND '1'='1 Query: SELECT * FROM users WHERE user_id = '5' AND '1'='1' (Always true if ID=5 exists) -> Response: "Found"

Similarly, find the column: 5' AND (SELECT COUNT(secret) FROM keys) > 0 AND '1'='1 Sql Injection Challenge 5 Security Shepherd